8m^2/3+16m^4/3

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Solution for 8m^2/3+16m^4/3 equation: 


m in (-oo:+oo)

(16*m^4)/3+(8*m^2)/3 = 0

16/3*m^4+8/3*m^2 = 0

t_1 = m^2

16/3*t_1^2+8/3*t_1^1 = 0

16/3*t_1^2+8/3*t_1 = 0

DELTA = (8/3)^2-(0*4*16/3)

DELTA = 64/9

DELTA > 0

t_1 = ((64/9)^(1/2)-8/3)/(2*16/3) or t_1 = (-(64/9)^(1/2)-8/3)/(2*16/3)

t_1 = 0 or t_1 = -1/2

t_1 = -1/2

m^2+1/2 = 0

1*m^2 = -1/2 // : 1

m^2 = -1/2

t_1 = 0

m^2+0 = 0

m^2 = 0

1*m^2 = 0 // : 1

m^2 = 0

m = 0

m = 0

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